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x^2+60x-960=0
a = 1; b = 60; c = -960;
Δ = b2-4ac
Δ = 602-4·1·(-960)
Δ = 7440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7440}=\sqrt{16*465}=\sqrt{16}*\sqrt{465}=4\sqrt{465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{465}}{2*1}=\frac{-60-4\sqrt{465}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{465}}{2*1}=\frac{-60+4\sqrt{465}}{2} $
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